Quote:
| Originally Posted by domski Cool. I'm up for trying this, but don't know what parts to buy.
|
You need to work out the voltage required by the IR emitter to power it, and add the resistor to drop any input voltage to that amount.
Too much power and it goes pop. Too little and it doesn't work.
Read this:
http://www.ngineering.com/LED_Calculators.htm